# Solve for a, 3b = (9/13)(2a-6)

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`3b=(9/13)(2a-6)=>` `(2a-6)=(13.3/9)b`

`=>` `2a=(13/3)b+6`

`=>` `a=(13/6)b+3` .

To solve for a from the expression `3b = (9/13)(2a-6)` express a in terms of b.

`3b = (9/13)(2a-6)`

=> `2a - 6 = (3b)*(13/9)`

=> `2a - 6 = (13b)/3`

=> `2a = (13b)/3 + 6`

=> `a = (13b)/6 + 3`

**The value of a in terms of the other variables is **`a = (13b)/6 + 3`