# What is the solution for `tan^-1 (sqrt 3) + tan^-1 x = pi/2`

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The value of x has to be determined such that `tan^-1(sqrt 3) + tan^-1 x = pi/2`

`tan^-1(sqrt 3) = 60`

=> `60 + tan^-1 x = 90`

=> `tan^-1 x = 30`

=> x = tan 30

=> x = `1/sqrt 3`

**The required value of x = `1/sqrt 3` **