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What is the solution for `tan^-1 (sqrt 3) + tan^-1 x = pi/2`
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The value of x has to be determined such that `tan^-1(sqrt 3) + tan^-1 x = pi/2`
`tan^-1(sqrt 3) = 60`
=> `60 + tan^-1 x = 90`
=> `tan^-1 x = 30`
=> x = tan 30
=> x = `1/sqrt 3`
The required value of x = `1/sqrt 3`
Posted by justaguide on December 25, 2011 at 10:12 PM (Answer #1)
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