Better Students Ask More Questions.
The solubility of sugar in water is 4.0 g/mL at room temperature, what is the maximum...
The solubility of sugar in water is 4.0 g/mL at room temperature, what is the maximum amount of sugar that will dissolve in 850 mL of water?
I don't know how to get the answer... if you could explain the way you got your answer it would be a lot of help... I have midterms in 3 days and I need to know how to do this.
1 Answer | add yours
Some solids dissolve in liquids in such a way that when the solids (called solute) are mixed in the liquid (called solvent) form a completely homogeneous mixture without any increase in the original volume of the liquid. For example substances like sugar and salt dissolve in water.
There is a limit to the maximum mass of a solute that can dissolve in given volume of solvent. This maximum dissoluble quantity of solute is dependent on the volume and temperature of solvent. If a quantity of solute more than this quantity is added to the solvent it does not dissolve in the liquid. It remains in the liquid in its solid state.
The solubility of a solvent in a solvent refers to the maximum mass of the solute that can dissolve in unit mass of the solvent at a given temperature. If we know the solubility of a substance in a liquid at a given temperature, we can calculate the maximum amount of the substance that can be dissolved in any given volume of the liquid at that temperature by simply multiplying solubility by the volume of the liquid.
The question specifies that solubility of sugar in water at room temperature is 4.0 g/mL, and we have to find out maximum quantity of sugar that will dissolve in 850 mL of water. As nothing is mentioned about temperature of 850 mL of water, we assume that it is at room temperature. Then the maximum quantity of sugar that can be dissolved in this water is given by the formula:
Maximums mass of sugar dissoluble in water
= (Solubility of sugar)*(Volume of water)
= 4.0*850 = 3400 g
Posted by krishna-agrawala on January 20, 2010 at 6:28 PM (Answer #1)
Related QuestionsSee all »
Join to answer this question
Join a community of thousands of dedicated teachers and students.