A small object, of mass 0.02kg at the top of a building 160 m high, is dropped from rest.

Assuming that the air resistance has magnitude 0·096 N, calculate

- the magnitude of the acceleration of the object,

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Here when the ball falls to the ground two forces will act on the ball. One is the weight of the ball which act downward which drives the ball to ground. In the upward direction air resistance will act on it.

Using Newtons second law of motion;

`darrF = ma`

`0.02xx9.81-0.096 = 0.02a`

`a = 5.01m/s^2`

*So the acceleration of the ball is `5.01m/s^2` and it act downward.*

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