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Sketch the following functions/relations and supply the domain and range. (Label...
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High School Teacher
A) From the defintion of the relation, we know that the domain is `(-oo,oo)`
B) From the following graph we can see that the range is `[0,oo)`
This can also be seen that noticing that x^2 is always non-negative and sqrt(x) is also non-negative
C) This relation is a function, and it is onto and into on the above defined domain and range.
D) It is not one to one because
Given x=1, then f(1)=sqrt(1)=1.
In the same time f(-1)=(-1)^2=1
Hence f(1)=f(-1) but 1 not equal (-1)
Please note that even if the graph show a gap, there is none. This a continuous function with value 0 at 0.
Posted by rcmath on May 8, 2012 at 4:45 PM (Answer #1)
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