Simplify `((p^2-9q^2)/(2pq +6q^2))divide((3p^2-8pq-3q^2)/(3pq+q^2))` `Thanks<br>` ` ` ` ` ` `   ` ` ` `       ` `

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`[(p^2-9q^2)/(2pq+6q^2)]/[(3p^2-8pq-3q^2)/(3pq+q^2)]`

`= (p^2-9q^2)/(2pq+6q^2)xx(3pq+q^2)/(3p^2-8pq-3q^2)`

 

`p^2-9q^2 = p^2-(3q)^2 = (p-3q)(p+3q)`

 

`3p^2-8pq-3q^2`

`= 3p^2-9pq+pq-3q^2`

`= 3p(p-3q)+q(p-3q)`

`= (p-3q)(3p+q)`

 

`= (p^2-9q^2)/(2pq+6q^2)xx(3pq+q^2)/(3p^2-8pq-3q^2)`

`= ((p+3q)(p-3q))/(2q(p+3q))xx(q(3p+q))/((p-3q)(3p+q))`

= 1/2

 

So the simplified answer is `1/2`

 

 

 

 

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