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Simplify the expression. State the excluded values, if any. w^2+6w+9/2w^2-18
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`=(w+3)/(2(w-3))` (assuming `w!=-3` )
Again, w=3 would make the denominator equal to zero, and the expression, undefined.
Hence, excluded values of w in this expression are `+-3` .
Posted by llltkl on July 21, 2013 at 4:56 PM (Answer #1)
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