simplify the expression `{(3x^2)^2(y^4)}/{3y^2}`

a. y^2 /3

b. x^4 * y^2 /1

c. 3x^2*y^2

d. 3x^4*y^2 <-- i think it is D

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To simplify this expression, we need to use the exponent laws `(ab)^m=a^mb^m` and `a^m/a^n=a^{m-n}` . This means we get:

`{(3x^2)^2y^4}/{3y^2}` distribute square into brackets

`={3^2x^4y^4}/{3y^2}` use division rule for 3 and y

`=3^{2-1}x^4y^{4-2}` simplify exponents

`=3^1x^4y^2` don't need the 1 for the exponent

`=3x^4y^2`

**The answer is D `3x^4y^2` .**

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