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simplify 2sin^2`theta` +2sin2`theta` +cos^2`theta` =0

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dimakatso-13 | eNotes Newbie

Posted July 15, 2013 at 2:07 PM via web

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2sin^2`theta` +2sin2`theta` +cos^2`theta` =0

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aruv | High School Teacher | (Level 2) Valedictorian

Posted July 15, 2013 at 3:32 PM (Answer #1)

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`sin^2(theta)+4sin(theta) cos(theta)+1=0`

`` Divide both side by `sin^2(theta)`












`x=-3.414 ,-.586`






`theta=npi+(91pi)/100`     n is  an integer.

if `cot(theta)=-.586`





`theta=mpi+(67pi)/100`   ,m is an integer.

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