simplify ∛108a^16b^9

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cubic root can be given as a power of (1/3).

`root(3)(108a^16b^9)`

`= root(3)(108)*root(3)(a^16)*root(3)(b^9)`

`= (108)^(1/3)*(a^16)^(1/3)*b^9(1/3)`

`= (27*4)^(1/3)*(a^9*a^7)^(1/3)*b^9(1/3)`

`= (3^3*4)^(1/3)*(a^15*a^2)^(1/3)*b^9(1/3)`

`= 3*4^(1/3)*a^5*a^(2/3)*b^3`

`= 3a^5b^3*a^(2/3)*4^(1/3)`

`= 3a^5b^3root(3)(a^2*4)`

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