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A signal travels through a transmission medium and its power is reduces to one...
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In optics, attenuation is related to the ratio of the input power to the output power of the signal. The equation for attenuation is:
Attenuation (dB) = 10 * log( input power / output power )
According to the problem statement, input power / output power = 1/4
Attenuation (dB) = 10 * log( input power / output power ) = 10 log( 1/4 ) = 10 * -0.6 = -6 dB.
Posted by kjcdb8er on January 19, 2011 at 10:20 AM (Answer #1)
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