Show that if `log_b a=c` and `log_y b=c` , then
`log_a y=c^-2` .
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`log_b a = c`
`log_y b = c`
`==> log_a y= c^-2`
We know that: `log_a b= (log_c b)/(log_c a)`
`` `log_a y=( log_b y)/(log_b a)= (log_b y)/C .........(1)`
`log_b y = (log_y y)/(log_y b) = 1/C .........(2)`
Now we will subsitute (2) into (1).
`==gt log_a y= (1/c)/c= 1/c^2 = c^-2 `
`==gt log_a y= c^-2`
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