Show that the end points of the latus rectum of the parabola x=2at, y=at^2 have parameters t=1 and t=-1.
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Thus equation f parabola
letus rectum passes trough focus and perpendcular to the axis of parabola.
y=a then `x^2=4a^2`
Thus end point of latus rectum of the parabola x=2at ,`y=at^2`
`x=+-2a and y=a` or when `t=+-1`
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