# A sample of oxygen collected over water at32C and 1038 torr has a volume of 0.741 L. What volume would the dry oxygen occupyunder standard conditions?The vapor pres-sure of water at 32C is 35.7...

A sample of oxygen collected over water at

32C and 1038 torr has a volume of 0.741 L.

What volume would the dry oxygen occupy

under standard conditions?The vapor pres-

sure of water at 32C is 35.7 torr.

Answer in units of L

### 1 Answer | Add Yours

Hello!

This problem can be solved using the combined gas law equation.

P1V1/T1 = P2V2/T2

***The key to this type of problem is to let the units be the same for the 1's and 2's.

*** at standard condition, T is 273.15 and P is 1atm or 760 torr

P1 = 1038 torr P2 = 760 torr

T1 = 32 + 273.15 = 305.15K T2 = 273.15 K

V1 = 0.741L V2 = ?

applying the formula above, substitue the values given.

(1038)(0.741)/ 305.15 = (760)(V2)/(273.15)

**V2 = 0.906 L**

hope this helps :)