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A sample of mercury with a mass of 114.0g was combined with 12.8g of oxygen gas, and...
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The reaction can be written as,
2Hg + O2 --> 2HgO
For the calculation the following molecular weights are considered.
Hg - 200.6 g/mol, O - 16 g/mol
according to the stoichiometric reaction, 401.2 g of Hg reacts with 32 g of O2 and produces 433.2 g of HgO
Hence the amount of O2 that will react with 114.0 g of Hg can be calculated as,
=> 9.1 g
Therefore the amount of excess O2 is = 12.8 g - 9.1 g
= 3.7 g
Posted by malagala on May 4, 2012 at 5:46 PM (Answer #1)
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