a=`root(3)(b+c+1)` Make B the subject. Please explain how you arrive at the answer.Thanks

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pramodpandey's profile pic

Posted on

we have

`a=(b+c+1)^(1/3)`

cube root (b+c+1)=(b+c+1)^(1/3)

Now raise power 3 both side ,we have

`(a)^3=((b+c+1)^(1/3))^3` ,

By law of exponents

`a^3=(b+c+1)^((1/3)xx3)`

`a^3=b+c+1`

`a^3-c-1=b`

`b=a^3-c-1`

ans.

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