Rewrite the quadratic equation y = 2x^2 + 10x + 9 into Standard Form to determine the Vertex.
Does it open up or down:
Is it taller or shorter than y = x^2:
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`=2(x^2+2xx x xx (5/2)+(5/2)^2-(5/2)^2+9/2)`
Vertex is `(-5/2,-7/2)`
It will open up.
Red is graph for `y=2x^2+10x+9`
Green is graph for `y=x^2`
Thus it taller than y = x^2 (since red is taller than green).
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