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Rewrite the quadratic equation in standard form by completing the square....
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High School Teacher
`=-1/3[x^2-18x-18]` We need a leading coefficient of 1
`=-1/3[x^2-18x+81-81-18]` Add/subtract 1/2 "b" squared
`=-1/3[(x-9)^2-99]` Rewrite trinomial as binomial squared
`=-1/3(x-9)^2+33` Distribute the -1/3
Thus the solution is `f(x)=-1/3(x-9)^2+33`
Posted by embizze on May 11, 2013 at 5:29 PM (Answer #1)
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