Please help me with Q.2 in the attached image.
1 Answer | Add Yours
We want to look for the minimum value of `cot^2A + cot^2B + cot^2C` given that `A + B + C = pi` .
We start with the following statement:
`(cotA - cotB)^2 + (cotB - cotC)^2 + (cotC - cotA)^2 >= 0` since a square of any number is greater than or equal to zero (and the terms are just sum of the squares). Expanding:
`(cot^2A - 2cotAcotB + cot^2B + cot^2B - 2cotBcotC + cot^2C + cot^2C - 2cotCcotA + cot^2A >= 0`
This implies that:
`2cot^2A + 2cot^2B + 2cot^2C >= 2cotAcotB + 2cotBcotC + 2cotCcotA`
`cot^2A + cot^2B + cot^2C >= cotAcotB + cotBcotC + cotCcotA`
Hence, we simply need to look for the value of the sum on the right side to get the minimum.
We know that `A + B + C = pi` . Hence, `A + B = pi - C.`
Then, `tan(A + B) = tan(pi - C) = -tanC` by the property of the tangent. Using sum identities:
`tan(A + B) = (tanA+tanB)/(1-tanAtanB) = -tanC` which implies that:
`tanA + tanB + tanC = tanAtanBtanC` .
Dividing both sides by `tanAtanBtanC` :
`(tanA)/(tanAtanBtanC) + (tanB)/(tanAtanBtanC) + (tanC)/(tanAtanBtanC) = 1`
`1/(tanBtanC) + 1/(tanAtanC) + 1/(tanAtanB) = 1`
`cotBcotC + cotAcotC + cotAcotB = 1`
`cot^2A + cot^2B + cot^2C >= 1`
The minimum value is 1.
Join to answer this question
Join a community of thousands of dedicated teachers and students.Join eNotes