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You have a relatively common question. I have taught high school science for 10 years and electricity is often a difficult topic for students to understand because of all the different units, formulas, etc.
Your question involves resistance and electrical power, which are two different things. When concerned with issues of resistance, Ohm's Law is used to calculate its resistance. Ohm's Law states that Voltage (measured in volts) = Current (in amperes) x Resistance (measured in Ohms). To solve for resistance, the formula would be rearranged and resistance = voltage / current. Watts are the unit of electrical power. Electrical power = current x voltage; therefore, the brightness of the bulb doesn't have to do with amount of resistance. It actually has to do with the amount of current and voltage.
My suggestion to you is to get a good set of notes on a level you understand (regardless of your grade level) and get some wire, batteries and light bulbs and try several configurations to help you understand. The very small lights like those that go on Christmas trees are the best for this small experiment.
I hope that this helps.
HI , MSDENNING THANKS FOR YOUR RESPONSE TO MY ANSWER.
BY READING UR ANSWER , IT MEANS THE 100 W BULB WILL CONSUME MORE VOLTAGE THAN 50W BULB AND THUS GROW MORE BRIGHTLY THAN 50W BULB.
AM I RIGHT ????
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