# The remainder when 10^2006+2006 divided by 9 is; A)0 B)2 C)5 D)6 E)7

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What is the remainder for `(10^2006 +2006)/9` ?

`(10^2006 +2006)/9=10^2006/9+2006/9`

Now a power of 10 divided by 9 always has a remainder of 1. ``

9*1+1=10

9*11+1=100

9*111+1=1000 etc...

So we have 1 plus the remainder when 2006 is divided by 9 which is 8.

The sum of 2 numbers will have the same remainder as the sum of the remainders.

So the remainder would be 9 -- but 9 is a factor of 9.

The remainder is 0 -- (A) is the answer.