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If the remainder of ax^2 + 3x + 18 when divided by x - 1 is 6, what is a.

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carolinesmiths | Student, Kindergarten | Salutatorian

Posted September 23, 2013 at 5:26 AM via web

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If the remainder of ax^2 + 3x + 18 when divided by x - 1 is 6, what is a.

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justaguide | College Teacher | (Level 2) Distinguished Educator

Posted September 23, 2013 at 5:29 AM (Answer #1)

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The remainder theorem gives the remainder of `(P(x))/(x - a)` as P(a).

When ax^2 + 3x + 18 is divided by x - 1 the remainder is 6.

P(1) = a*1 + 3*a + 18 = 6

=> a + 21 = 6

=> a = -15

The required value of a = -15

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