f(x)=ln (1+sin ^2x )
what is g'(x)?
g(x)=integral S (pi /4 down _ asin x up ) f(t)dt
1 Answer | Add Yours
We know Leibnitz rule for differentiation under integral sign.
Let differentiation under integral sign is valid.
differentiate g(x) with respect to x,we have By Leibniz rule,
`(d(ln(1+sin^2t)))/dx=` partial derivative of ln(1+sin^2t) with respect to
x = 0
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