Reduce to normal form and fine the distance of the line from the origin: 5x+12y+39=0 Topic: Math 1 Answer | Add Yours samhouston | Middle School Teacher | (Level 1) Associate Educator Posted on October 3, 2012 at 2:39 PM (Answer #1) 5x + 12y + 39 = 0 In slope-intercept form: 12y = -5x - 39 y = -5/12x - 13/4 5x + 12y + 39 = 0 In slope-intercept form: 12y = -5x - 39 y = -5/12x - 13/4 We’ve answered 288,284 questions. We can answer yours, too. Ask a question

samhouston | Middle School Teacher | (Level 1) Associate Educator Posted on October 3, 2012 at 2:39 PM (Answer #1) 5x + 12y + 39 = 0 In slope-intercept form: 12y = -5x - 39 y = -5/12x - 13/4 5x + 12y + 39 = 0 In slope-intercept form: 12y = -5x - 39 y = -5/12x - 13/4