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Evaluate the limit : `lim_(x->0) (18+7/x)`
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High School Teacher
If `x` is a small positive number, then `7/x` and therefore `18+7/x` are both large positive numbers. However, if `x` is a small negative number, then `7/x` and therefore `18+7/x` are both large negative numbers. Expressed mathematically,
`lim_(x->0^+) (18+7/x)=oo,` but
Therefore the limit does not exist.
Posted by degeneratecircle on January 23, 2013 at 3:52 AM (Answer #2)
The limit `lim_(x->0)18+7/x` has to be determined.
As `x->0` , `1/x->oo` .
This gives `lim_(x->0)18+7/x = 18 +oo = oo`
The limit `lim_(x->0)18+7/x = oo`
Posted by justaguide on January 23, 2013 at 3:12 AM (Answer #1)
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