a rectangle athletic field is twice as long as it is wide. If the perimeter of the athletic field is 180 yards, what are it's dimensions?
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You need to use the formula of perimeter of rectangle, such that:
`P = 2(L + w)`
`L` represents the length of rectangle
`w` represents the width of rectangle
The problem provides the information that the rectangle athletic field is twice as long as it is wide, hence, translating into equation yields:
`L = 2w`
Replacing 180 for perimeter and `2w` for `L` in equation of perimeter, yields:
`180 = 2(2w + w) => 180 = 2*3w => 180 = 6w => w = 180/6 => w = 30 yards => L = 2*30 => L = 60` yards
Hence, evaluating the dimensions of the rectangle athletic field, under the given conditions, yields `L = 60` yards and `w = 30` yards.
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