The reaction 2X + 3Y ----> Z is first order in X and second order in Y with k=0.42.
What will the rate of the reaction be if [X] = 0.15 M and [Y] = 0.633M?
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The first thing we need to do is to set up the rate law equation based on the order of the reaction. The general rate law is
Rate = k[X]^m [Y]^n
Now we can substitute in the values we know
Rate = 0.42 [X]^1 [Y]^2
To find the general rate law. Now we can plug in the concentrations given and solve for the rate.
Rate = 0.42 [0.15] [0.633]^2
And then solve for rate
Rate = 0.0252 M/s
As the concentrations change, the value of the rate will change but the general rate law will not change. The value of the rate constant, k, will be constant are the same conditions. If you change the temperature then the value of k will change but the orders of the reaction will not.
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