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The reaction 2CO2 *forward and backward arrows* 2CO + O2 has K = 6.4 x 10^-17.At...

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ceeee | Student, College Freshman | (Level 1) Honors

Posted May 18, 2012 at 2:19 AM via web

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The reaction 2CO2 *forward and backward arrows* 2CO + O2 has K = 6.4 x 10^-17.

At equilibrium, the pressure of CO = 2.6 x 10^-6 atm and the pressure of CO2 = 0.25 atm. What is the pressure of O2?

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thilina-g | College Teacher | (Level 1) Educator

Posted May 18, 2012 at 3:47 AM (Answer #1)

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This is a gas phase equilibrium. I am assuming you have given

Kp = 6.4 x 10^(-17) in atm units.

2CO2 <------------->2CO +O2

Kp = (P_CO)^2 x (P_O2) / (P_CO2)^2

6.4 x 10^(-17) = (2.6 x 10^(-6))^2 x (P_O2) / (0.25)^2

P_O2 = 5.917 x 10^(-7) atm.

 

Therefore, pressure of O2 is 5.917 x 10^(-7) atm.

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