The reaction 2CO2 *forward and backward arrows* 2CO + O2 has K = 6.4 x 10^-17.

At equilibrium, the pressure of CO = 2.6 x 10^-6 atm and the pressure of CO2 = 0.25 atm. What is the pressure of O2?

### 1 Answer | Add Yours

This is a gas phase equilibrium. I am assuming you have given

Kp = 6.4 x 10^(-17) **in atm units.**

2CO2 <------------->2CO +O2

Kp = (P_CO)^2 x (P_O2) / (P_CO2)^2

6.4 x 10^(-17) = (2.6 x 10^(-6))^2 x (P_O2) / (0.25)^2

P_O2 = 5.917 x 10^(-7) atm.

**Therefore, pressure of O2 is 5.917 x 10^(-7) atm. **

**Sources:**

### Join to answer this question

Join a community of thousands of dedicated teachers and students.

Join eNotes