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Ratio and proportion.....If x/a = y/b = z/c, prove that- (Please open the link below...

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itssnigdha | Student, Grade 11 | eNoter

Posted February 23, 2010 at 6:54 PM via web

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Ratio and proportion.....

If x/a = y/b = z/c, prove that-

(Please open the link below to view the whole problem.)

http://mathstest.4t.com/5.gif

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neela | High School Teacher | Valedictorian

Posted February 23, 2010 at 7:08 PM (Answer #1)

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Let x/a=y/b=z/c each equal to k.

Then x= ak,y=bl and z =ck.  Substituting in {(a^2x^2-(b^2y^2+c^2y^2/(a^2x-b^2y+c^2)}#/2

= {[a^2(ak)^2-b^2(bk)^2+c^2(ck)^2]/[a^2a-kb^2bk+c^2ck]}(3/2)

={(a^3-b^3+c^3)k^2/ (a^3-b^3+c^3)k}^(3/2)

=k^(3/2) = (k^3)^(1/2), as x/a=y/b=z/c each equal to k.

= (xyz/abc)^(3/2) as

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amitparmar | Student, Undergraduate | eNoter

Posted February 24, 2010 at 6:02 AM (Answer #2)

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If x/a = y/b = z/c,

let x/a = y/b = z/c=k

we have,

putting above values in lhs then we have answer.

 

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