The radius of the earth is approximately 6371km.If the international space station (ISS) is orbiting 353 km above the earth, find the distance from the ISS to the horizon.
I think I can use the Pythagorean Theorem to solve for x, but I am not sure how to prove that the triangle is right. Since all three points do not rest on the circle.
Thank you for the help.
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You can use the pythagorean theorem to solve for the distance to the horizon. Any segment drawn from a point of tangency to the center is always perpendicular. Therefore, connect the segment from the point of tangency to the center, this is also a radius. Now, there is formed a right triangle in which one leg is the segment from point of tangency to center = 6371 km and the hypotenuse which is 6724 km (6371+353).
Use pythagoream theorem to find the horizon (leg) x.
`x^2 + 6371^2 = 6724^2`
` ` `x^2 = 4622535`
`x = 2150.00814` km
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