Question is in the explanation box, please help!!
A 68 kg tight-rope walker stands in the middle of the tight rope. The rope sags such that each end of the rope is 16o below the horizontal.
The rope must be able to support what minimum force?
1 Answer | Add Yours
Let T be the tension in rope and Tsin(160) is the vertical component of the tension in rope on either side so that 2Tsin(160) = 68 or T=34/sin(160)
=> T = 99.41N
The rope must be able to support a minimum of 99.41N, say 100N
We’ve answered 315,806 questions. We can answer yours, too.Ask a question