# What would be the density of the resulting liquid if 10.0 ml of ethylyne glocol, 1.114 gm/mL, is added to 100.0 mL of pure water, 1.00 g/mL?

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To answer this question we must make an assumption. We must assume that within the range of significant digits, the volume of the new liquid is equal to the sum of the volume of the ethylene glycol and the water.

First we calculate the mass of each liquid:

`rho = m/V => m = rho V`

`m = 1.114 g/(mL) * 10.0 mL = 11.14 g`

`m = 1.00 g/(mL) * 100.0 mL = 100.0 g`

We then divide the total mass by the total volume:

`(11.14g + 100.0g)/(110.0 mL) = 1.01 g/(mL)`

Therefore, the mass of the new mixture will be 1.01 g/mL