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Quadratic equation The height of a rocket in metres can be found by the function ...
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`h(t) = -4.9t^2+ 540t + 25`
When the height is 0;
`-4.9t^2+ 540t + 25 = 0`
The solution for above quadratic equation is given by;
`t = ((-540)+-sqrt(540^2-4*(-4.9)*25))/(2*(-4.9))`
`t = -0.0463` OR `t = 110.25`
Usually time is a positive component. So t = -0.0463 not acceptable.
So the rocket height is 0 when the time is 110.25 seconds.
Posted by jeew-m on October 30, 2012 at 5:03 AM (Answer #1)
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