Q. A plane flies round- trip between Los Angeles and Namulevu,Vanuavinaka.The plane takes off at 12:50 P.M. Los Angeles time and lands at 6:50 P.M. Namulevu time.On the return trip, it takes off at 1:50 A.M. Namulevu time and lands at 6:50 P.M. Los Angeles time.Assume that the flight time is same in both the directions and that the plane flies in a straight line at an average speed of 520 mi/hr.

What length of time is the flight(one way,as measured by the passengers)?

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The plane takes off at 12:50 PM Los Angeles time and lands at 6:50 P.M. Namulevu time. On the return trip, it takes off at 1:50 A.M. Namulevu time and lands at 6:50 P.M. Los Angeles time.

Let Namulevu lie T hours ahead of Los Angeles. And express time in the 24 Hour clock.

On the flight from Los Angeles to Namulevu, the plane takes off at 12:50 + T Namulevu time and lands at 18:50. The duration of the flight is 6 - T hrs. On the reverse flight, the plane takes off at 1:50 A.M. Namulevu time and lands at 18:50 + T Namulevu time. The duration of the flight is 17 + T hours.

The time taken by the flight is the same in both the directions.

6 - T = 17 + T

=> T = -5:30

The length of time in flight for the passengers is 11:30 hours.

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