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The balanced chemical equation for the reaction between `P_4 ` and `NaOH` is:
` (A)` ` (B)`
Let the oxidation number of phosphorus in the product A be x. Then,
Again, let the oxidation number of phosphorus in the product B be y. Then, `(+1)+(+1)*2+y+(-2)*2=0`
Hence, the oxidation number of phosphorus in the products `A` and `B` is -3,+1.
Therefore, option c) is the correct answer.
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