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Q. A mixture of `NaCl` and `NaI` when heated with `H_2SO_4` , produced the same...

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user8235304 | Student, Grade 11 | (Level 1) Valedictorian

Posted July 10, 2013 at 5:34 PM via web

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Q. A mixture of `NaCl` and `NaI` when heated with `H_2SO_4` , produced the same weight of sodium sulphate as that of the original mixture.Calculate percentage of `NaI` in the mixture.

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llltkl | College Teacher | (Level 3) Valedictorian

Posted July 10, 2013 at 6:10 PM (Answer #1)

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Let, the total amount of mixture of NaCl and NaI taken initially was x g, out of which amount of NaCl was y g. So, amount of NaI in the initial mixture was (x-y) g.

Balanced chemical reactions of NaCl and NaI with H2SO4 are as follows:

2NaCl + H2SO4 -> Na2SO4 + HCl

2NaI + H2SO4 -> Na2SO4 + HI

Amount of components obtainable/reacting freom stoichiometric considerations are as follows:

NaCl          Na2SO4         NaI            Na2SO4

------      ---------   ----------     ------------

117          142             300                 142 

`y`        `(142*y)/117`       `(x-y) `           `(142*(x-y))/300`

By condition, `(142*y)/117+(142*(x-y))/300 = x` ` `

`rArr 14200y+5538x-5538y=11700x ` (LCM of 117 and 300 is 11700)

`rArr 8662y=6162x`

`(y/x)*100=(6162/8662)*100=71.14`

This is the percent (by mass) of NaCl present in the original mixture.

Therefore, percent (by mass) of NaI present in the original mixture was 100-71.14=28.86.

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