Find the gradient for a tangent to the graph of `y= e^x log(x^2)` .

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Given a function f(x), f'(a) is the gradient of the tangent to the graph of the curve at the point where x = a.

For the function `y = e^x*log(x^2)`

y' = `e^x*log(x^2) + (e^x)*(1/x^2)*(2x)`

= `e^x*log(x^2) + (2*e^x)/x`

**This is the gradient of the tangent to the graph represented by the function `y = e^x*log(x^2)` .**

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