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Find the gradient for a tangent to the graph of  `y= e^x log(x^2)` .

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user8235304 | Student, Grade 11 | Valedictorian

Posted July 5, 2013 at 6:08 PM via web

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Find the gradient for a tangent to the graph of  `y= e^x log(x^2)` .

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justaguide | College Teacher | (Level 2) Distinguished Educator

Posted July 5, 2013 at 6:16 PM (Answer #1)

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Given a function f(x), f'(a) is the gradient of the tangent to the graph of the curve at the point where x = a.

For the function `y = e^x*log(x^2)`

y' = `e^x*log(x^2) + (e^x)*(1/x^2)*(2x)`

= `e^x*log(x^2) + (2*e^x)/x`

This is the gradient of the tangent to the graph represented by the function `y = e^x*log(x^2)` .

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