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Differentiate `ln( 1 + theta)` with respect to `sin^-1theta` .
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The expression `ln(1+theta)` has to be differentiated with respect to `sin^-1theta` .
If `y = ln(1+ theta)` , `x = sin^-1 theta` and `dy/dx` has to be determined.
= `((d ln(1+ theta))/(d theta))/((d(sin^-1theta))/(d theta))`
= `(1/(theta+1) )/(1/(sqrt(1-theta^2)))`
The required derivative `((d ln(1+ theta))/(d theta))/((d(sin^-1theta))/(d theta)) = sqrt(1- theta)/sqrt(1+theta)`
Posted by justaguide on June 27, 2013 at 4:53 PM (Answer #1)
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