Q. A balloon is moving up with a speed 60 m/s.When the balloon is at a height 225 m above the ground a stone is thrown horizontally with a speed 40 m/s with respect to balloon.
a) The horizontal displacement of the stone when it is at the top of its trajectory.
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At the moment of throwing, the stone will possess two components of velocity,
1. Upward, 60m/s
2. Horizontal, 40 m/s
At the top of its trajectory, the vertical component of velocity is zero. Applying laws of motion for this component,
t = 60/g =60/9.81=6.1155 s
This is the time to reach the top of its trajectory.
a) Horizontal range covered by the stone in this time = horizontal velocity * time
Therefore, the horizontal displacement of the stone when it is at the top of its trajectory is 244.6 m.
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