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Q.A ball of mass m is moving horizontally within a horizontal trough.The coefficient of...

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user8235304 | Student, Grade 11 | (Level 1) Valedictorian

Posted July 31, 2013 at 4:22 PM via web

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Q.A ball of mass m is moving horizontally within a horizontal trough.The coefficient of friction between the ball and both the trough surfaces is `mu` .Find the retardation.

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justaguide | College Teacher | (Level 2) Distinguished Educator

Posted August 10, 2013 at 5:26 PM (Answer #1)

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The ball of mass m is moving horizontally within the horizontal trough as shown in the figure.

The weight of the ball is equal to m*g and acts in a vertically downwards direction. The weight of the ball can be split into components that are at right angles to the surfaces inclined at 60 degrees to the horizontal and parallel to them. The component that is at perpendicular to the surface is equal to the normal force. This is given by `m*g*cos 60 = (m*g)/2` . As the coefficient of friction is `mu` , the retardation of the ball is `2*(m*g)/2*mu = mu*m*g`

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