Better Students Ask More Questions.
Q. A ball is dropped from rest from the top of a tower.The distance covered in the last...
1 Answer | add yours
Best answer as selected by question asker.
Since, the ball is dropped from rest from the top of a tower, the total distance travelled by the ball is equal to the height of the tower.
Let the total distance `S` is covered in `n` seconds, then:
So, `S=1/2*gn^2` .................(i)
Similarly, let the total distance covered in `(n-1)` secs. is `S'` , then:
Hence, the distance covered in the last second is given by `S-S'` .
According to the given problem:
Substituting the values of `S` and `S'` from equations (i) and (ii) we get:
Plugging `g=9.81m/s^2` in the above equation we get:
Putting `n=5.6` in equation (i),
Therefore, the height of the tower is approximately 153.82 m.
Posted by llltkl on August 3, 2013 at 12:50 PM (Answer #1)
Join to answer this question
Join a community of thousands of dedicated teachers and students.