Put in algebraic equation: The difference of 3 times a number y and 2 equals 19.
I can't figure this out to help my daughter. Thanks
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It is worded a little strangely, but what they are saying is that 3 times the unknown number is 19 more than 2.
Add 19 to each side of the equation; you then have 3y=21.
Divide each side by 3, and y=7
You could also look at it as 3y-2=19; add 2 to each side, and once again you have 3y=21
The concept of three times a number y and two equals 19 is simply written as
3y+2 = 19
To find the solution to this equasion you simply subtract 2 from each side which leaves you with 3y=17 . At this juncture you divide each side by 3 and that gives you Y=17/3
The soultion would be Y= 5 2/3
The equation would be 3y+2=19
If you want to know the solution of the alegbraic equation, here it is:
3y/3=17/3 (divide 3)
y= 5 2/3 //
The difference of 3 times a number y and 2 equals 19.
Difference = subtraction
times = multiplication
3 times a number y = 3y
Difference of 3 times a number y and 2 = 3y - 2
This equal 19 so
3y - 2 = 19
3y = 19 + 2 = 21
y = 21/3 = 7
The difference of 3 times a number y and 2 equals 19
3y - 2 = 19
move like terms to the same side
3y = 19 + 2
3y = 21
divide by 3
y = 7
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