# A punch recipe calls for 1.5 L of fruit juice and 700mL of gingerale. How much fruit juice is needed for 2.5 L of gingerale?Note:1 L = 1000mL

enotechris | College Teacher | (Level 2) Senior Educator

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This is a proportions problem,  Fruit Juice / Gingerale.  First, get all your units the same, so 700ml = .7 L. Now set up the proportion:

1.5 L Fruit Juice  / .7 L Gingerale   = x L Fruit Juice / 2.5 L Gingerale, so

1.5 / .7 = x / 2.5

.7x = 1.5 * 2.5

.7x = 3.75

x = 5.36 L

atyourservice | Student, Grade 11 | (Level 3) Valedictorian

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A punch recipe calls for 1.5 L of fruit juice and 700mL of gingerale. How much fruit juice is needed for 2.5 L of gingerale?

Note:1 L = 1000mL

1.5 x 1000 = 1500 ml

2.5 x 1000 = 2500 ml

1500/700 = 2.14285714

2.14285714 x 2500 = 5357.14285

5357.14285 / 1000 = 5.35714285 or 5.36 L

revolution | College Teacher | (Level 1) Valedictorian

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Lets convert liters to milliliters

If 1L=1000ml

So, 1.5L= 1500ml

2.5L= 2500ml

This involves direct proportion

x/2500= 1500/700

multiply by 2500ml

x= 1500/700*2500

= 5357ml

= 5.357 L