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Prove that `1/(sec^2x) = sin^2x*cos^2x + cos^4x`
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The identity `1/(sec^2x) = sin^2x*cos^2x + cos^4x` has to be proved.
`sin^2x*cos^2x + cos^4x`
=> `(1 - cos^2x)*cos^2x + cos^4x`
=> `cos^2x - cos^4x + cos^4x`
This proves that `1/(sec^2x) = sin^2x*cos^2x + cos^4x`
Posted by justaguide on June 5, 2012 at 4:17 PM (Answer #1)
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R:H:S = sin²x.cos²x + cos⁴x
we know that sin²x+cos²x=1
Posted by lochana2500 on June 29, 2012 at 4:08 PM (Answer #2)
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