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Prove:`sin8A=8sinA*cosA*cos2A*cos4A`sin8A=8sinA*cosA*cos2A*cos4A

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spsaroj | Student, Grade 10 | Honors

Posted June 22, 2012 at 1:01 PM via web

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Prove:`sin8A=8sinA*cosA*cos2A*cos4A`

sin8A=8sinA*cosA*cos2A*cos4A

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embizze | High School Teacher | (Level 1) Educator Emeritus

Posted June 22, 2012 at 3:45 PM (Answer #1)

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We want to prove `sin8A=8sinA*cosA*cos2A*cos4A`

`sin8A=sin(4A+4A)`

`=sin4Acos4A+sin4A+cos4A` :sum of angles identity

`=2sin4Acos4A`

`=2(2sin2Acos2Acos4A)` ``: double angle identity

`=4sin2Acos2Acos4A`

`=4(2sinAcosAcos2Acos4A)` : double angle identity

`=8sinAcosAcos2Acos4A` as required.

** In general, when proving trigonometric identities you start with one side, and by using allowable algebraic manipulations and other trigonometric identities, you transform that side into the other side.

 

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