# Prove:`sin8A=8sinA*cosA*cos2A*cos4A`sin8A=8sinA*cosA*cos2A*cos4A

### 1 Answer | Add Yours

We want to prove `sin8A=8sinA*cosA*cos2A*cos4A`

`sin8A=sin(4A+4A)`

`=sin4Acos4A+sin4A+cos4A` :sum of angles identity

`=2sin4Acos4A`

`=2(2sin2Acos2Acos4A)` ``: double angle identity

`=4sin2Acos2Acos4A`

`=4(2sinAcosAcos2Acos4A)` : double angle identity

`=8sinAcosAcos2Acos4A` as required.

** In general, when proving trigonometric identities you start with one side, and by using allowable algebraic manipulations and other trigonometric identities, you transform that side into the other side.

**Sources:**