The product of two numbers is 30. If one of the numbers is 6/17, what is the other number?

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The product of two numbers = 30

Let one of the number be x.

The second number = 6/17

Then,

6/17 * x = 32

Now multiply by 17/6 :

\==> x= 32*17/6

==>** x = 272/ 3**

Product of two numbers is 30. One of the number is 6/17.

Therefore product = 30 divided by 6/17 is the other number.

So the other number = 30 / (6/17) = 30*17/6 = (30/6)17 = 85.

So 85 is the other number and the product of 85 and 6/17 is 85*(6/17) = (85/17)*6 = 30.

We are given that two numbers are multiplied to give 30 as the result and that one of the numbers is 6/17. Let the other number, which is the one we have to determine, be X.

Using the information given we can derive the expression X*(6/17)=30

Multiply both sides of the equation by 17/6, we get:

X = 30*(17/6). Simplifying, we get X= 5*17 = 85

**Therefore the other number is 85.**

Let the unknown number be Y.

it follows that Y*6/17 = 30

Y*6/17*17/6=30*17/6

therefore Y=5*17

Y=85

From the question, we have been given one of the number as 6/17, now let the unknown number be any alphabet (let say m). Since their product is 30, that implies 6/17*m =30. Multiplying the R.H.S gives 6m/17 =30. When we cross multiply, we get 6m =30 * 17. With this we achieve 6m = 510. Making m the subject, we divide through by 6. i.e 6m/6 = 510/6. And this gives m = 85. So the other number is 85.

We'll note the product of the 2 numbers as P:

P = a*b

We'll put one of the factors as 6/17.

Since there is not specified what factor to be the ratio 6/17, we'll put a = 6/17.

We also know that the product of the factors is 30.

We'll put P = 30.

30 = 6b/17

We'll multiply both sides by 17:

30*17 = 6b

We'll divide by 6 both sides and we'll use the symmetric property:

b = 5*17

b = 85

**The other factor is b = 85.**

let the2nd no= x

then

6/17 * x=30

x =30*17/6 then

x = 85

AS 6/17 *85 =30

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