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A power station delivers 600 kW of power at 12,000 V to a factory.  What current is...

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lkehoe | (Level 1) Valedictorian

Posted April 3, 2013 at 4:26 AM via web

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A power station delivers 600 kW of power at 12,000 V to a factory.  What current is required to deliver this power The wires from the power station to the factory have a total resistance of 3.0 ohm.  What is the power dissipated by the current in the wires?

 

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justaguide | College Teacher | (Level 2) Distinguished Educator

Posted April 3, 2013 at 4:38 AM (Answer #1)

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The power station delivers 600 kW of power at 12000 V to a factory. Power (P) is related to current (I) and voltage (V) by: P = V*I. Substituting the values in the problem

600000 = 12000*I

=> I = 600000/12000 = 50 Amps

The current required to deliver the power is 50 A.

The total resistance of the wires that carry the current from the power station to the factory is 3 ohms. The power dissipated by the wires is P = R*I^2 = 3*50^2 = 3*2500 = 7500 W

The power dissipated is 7.5 kW

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