- Download PDF
A power station delivers 600 kW of power at 12,000 V to a factory. What current is required to deliver this power The wires from the power station to the factory have a total resistance of 3.0 ohm. What is the power dissipated by the current in the wires?
1 Answer | Add Yours
The power station delivers 600 kW of power at 12000 V to a factory. Power (P) is related to current (I) and voltage (V) by: P = V*I. Substituting the values in the problem
600000 = 12000*I
=> I = 600000/12000 = 50 Amps
The current required to deliver the power is 50 A.
The total resistance of the wires that carry the current from the power station to the factory is 3 ohms. The power dissipated by the wires is P = R*I^2 = 3*50^2 = 3*2500 = 7500 W
The power dissipated is 7.5 kW
We’ve answered 320,043 questions. We can answer yours, too.Ask a question