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the position of an object at any time is given by the equation s(t)=3t^3-2t+4 find the...
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(Level 1) Associate Educator, Expert, Newton
The velocity of the object is the derivative of its position function.
The acceleration of the object is the derivative of its velocity function.
The derivative of `a x^n` is `a n x^(n-1)`
The derivative of `c x ` is c
The derivative of a constant is 0
`v(t)=s'(t)=9 t^2 - 2`
`a(t)=v'(t)=18 t `
Posted by mlehuzzah on April 10, 2013 at 2:03 AM (Answer #1)
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