Better Students Ask More Questions.
Plz help..The internal and external diameters of a hollow hemispherical vessel are 14...
3 Answers | add yours
High School Teacher
The hemispherical vessal has two surfaces. Internal and external.
Let R and r be the eadius of the internal and external radius. Also radius is half the diameter.
The outer surface area of the hemisphere = (1/2)( 4*pi*R^2 ) =2 pi*(21/2)^2 = 2770.88472/4 sq cm = 692.72118
The area of the internal hemisphere = (1/2)*(4pir^2) = 2pi*r^2 = 2pi*(14/2)^2 = 1231.50432/4 sq cm = 307.8760801 sqcm
The ring or edge area = pi *R^2-Pir^2 = pi*(R^2-r^2) = pi*(21^2-14^2)/4 =769.6903001/4 = 192.422575 .
Thererefore the total area = 692.72118+307.87608+192.422575 = 1193.019835 sq cm
Therefore the plating cost @ Rs 1.60 for the above total area = 1193.019835 sq cm * Rs1.6sqcm = Rs 1908.83
Posted by neela on December 27, 2009 at 5:30 PM (Answer #1)
Hi, for any homework help, assignment help, dissertation help, visit our website http://www.helpwithassignment.com. We offer online tutoring, assignment help, homework help, dissertation help and thesis help in almost all the subjects. We offer services for a range of subjects for K-12, College and University.
Posted by abertfrank on June 21, 2010 at 9:39 PM (Answer #2)
This is a basic math problem if you are facing trouble solving this than you should hire one of the online math tutors available on internet.At this students can submit their questions online to get the answers. They can also get elaborate explanations on particular topics required from the tutors. The students can observe the solved examples online and solve similar problems. They can also clarify their doubts regarding the concepts involved from the tutors immediately.
Posted by kanishkporwal on October 5, 2011 at 6:37 PM (Answer #3)
Join to answer this question
Join a community of thousands of dedicated teachers and students.