# Please solve this. 2^x = 13

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To solve an equation containing a variable exponent, isolate the exponential quantity. Then take natural (base *e*) log on both sides.

`2^x = 13`

`rArr ln(2^x)=ln(13)`

`rArr xln2=ln13`

`rArr x=ln13/ln2`

`rArr x ~~ 3.70`

**Therefore, the value of x is approximately 3.70.**

**Sources:**